Substr
(substring) function copies a portion of one string to another. In a high level language, this function usually takes the form:DestStr := Substr(SrcStr,Index,Length);
where:
DestStr
is the name of the string variable where you want to store the substring,
SrcStr
is the name of the source string (from which the substring is to be taken),
Index
is the starting character position within the string (1..length
(SrcStr
)), and
DestStr
.
The following examples show how Substr
works.
SrcStr := 'This is an example of a string'; DestStr := Substr(SrcStr,11,7); write(DestStr);
This prints 'example'. The index value is eleven, so, the Substr
function will begin copying data starting at the eleventh character in the string. The eleventh character is the 'e' in 'example'. The length of the string is seven.
This invocation copies the seven characters 'example' to DestStr
.
SrcStr := 'This is an example of a string'; DestStr := Substr(SrcStr,1,10); write(DestStr);
This prints 'This is an'. Since the index is one, this occurrence of the Substr
function starts copying 10 characters starting with the first character in the string.
SrcStr := 'This is an example of a string'; DestStr := Substr(SrcStr,20,11); write(DestStr);
This prints 'of a string'. This call to Substr
extracts the last eleven characters in the string.
What happens if the index and length values are out of bounds? For example, what happens if Index
is zero or is greater than the length of the string? What happens if Index
is fine, but the sum of Index
and Length
is greater than the length of the source string? You can handle these abnormal situations in one of three ways: (1)ignore the possibility of error; (2)abort the program with a run-time error; (3)process some reasonable number of characters in response to the request.
The first solution operates under the assumption that the caller never makes a mistake computing the values for the parameters to the Substr
function. It blindly assumes that the values passed to the Substr
function are correct and processes the string based on that assumption. This can produce some bizarre effects. Consider the following examples, which use length-prefixed strings:
SourceStr :='1234567890ABCDEFGHIJKLMNOPQRSTUVWXYZ'; DestStr := Substr(SourceStr,0,5); Write('DestStr');
prints '$1234'. The reason, of course, is that SourceStr
is a length-prefixed string. Therefore the length, 36, appears at offset zero within the string. If Substr
uses the illegal index of zero then the length of the string will be returned as the first character. In this particular case, the length of the string, 36, just happened to correspond to the ASCII code for the '$' character.
The situation is considerably worse if the value specified for Index
is negative or is greater than the length of the string. In such a case, the Substr
function would be returning a substring containing characters appearing before or after the source string. This is not a reasonable result.
Despite the problems with ignoring the possibility of error in the Substr
function, there is one big advantage to processing substrings in this manner: the resulting Substr
code is more efficient if it doesn't have to perform any run-time checking on the data. If you know that the index and length values are always within an acceptable range, then there is no need to do this checking within Substr
function. If you can guarantee that an error will not occur, your programs will run (somewhat) faster by eliminating the run-time check.
Since most programs are rarely error-free, you're taking a big gamble if you assume that all calls to the Substr
routine are passing reasonable values. Therefore, some sort of run-time check is often necessary to catch errors in your program. An error occurs under the following conditions:
Index
) is less than one.
Index
is greater than the length of the string.
Substr
length parameter (Length
) is greater than the length of the string.
Index
and Length
is greater than the length of the string.
An alternative to ignoring any of these errors is to abort with an error message. This is probably fine during the program development phase, but once your program is in the hands of users it could be a real disaster. Your customers wouldn't be very happy if they'd spent all day entering data into a program and it aborted, causing them to lose the data they've entered. An alternative to aborting when an error occurs is to have the Substr
function return an error condition. Then leave it up to the calling code to determine if an error has occurred. This technique works well with the third alternative to handling errors: processing the substring as best you can.
The third alternative, handling the error as best you can, is probably the best alternative. Handle the error conditions in the following manner:
Index
) is less than one. There are two ways to handle this error condition. One way is to automatically set the Index
parameter to one and return the substring beginning with the first character of the source string. The other alternative is to return the empty string, a string of length zero, as the substring. Variations on this theme are also possible. You might return the substring beginning with the first character if the index is zero and an empty string if the index is negative. Another alternative is to use unsigned numbers. Then you've only got to worry about the case where Index
is zero. A negative number, should the calling code accidentally generate one, would look like a large positive number.
Substr
function should return an empty string. Intuitively, this is the proper response in this situation.
Substr
length parameter (Length
) is greater than the length of the string. -or-
Index
and Length
is greater than the length of the string. Points three and four are the same problem, the length of the desired substring extends beyond the end of the source string. In this event, Substr
should return the substring consisting of those characters starting at Index
through the end of the source string.
The following code for the Substr
function expects four parameters: the addresses of the source and destination strings, the starting index, and the length of the desired substring. Substr
expects the parameters in the following registers:
ds:si- The address of the source string.
es:di- The address of the destination string.
ch- The starting index.
cl- The length of the substring.
Substr returns the following values:
es:di
.
Substr
clears the carry flag if there were no errors. Substr
sets the carry flag if there was an error.
Substr
preserves all the registers.
If an error occurs, then the calling code must examine the values in si, di
and cx
to determine the exact cause of the error (if this is necessary). In the event of an error, the Substr
function returns the following substrings:
Index
parameter (ch
) is zero, Substr
uses one instead.
Index
and Length
parameters are both unsigned byte values, therefore they are never negative.
Index
parameter is greater than the length of the source string, Substr
returns an empty string.
Index
and Length
parameters is greater than the length of the source string, Substr
returns only those characters from Index
through the end of the source string. The following code realizes the substring function.
; Substring function. ; Substring function. ; ; HLL form: ; ;procedure substring(var Src:string; ; Index, Length:integer; ; var Dest:string); ; ; Src- Address of a source string. ; Index- Index into the source string. ; Length- Length of the substring to extract. ; Dest- Address of a destination string. ; ; Copies the source string from address [Src+index] of length ; Length to the destination string. ; ; If an error occurs, the carry flag is returned set, otherwise ; clear. ; ; Parameters are passed as follows: ; ; DS:SI- Source string address. ; ES:DI- Destination string address. ; CH- Index into source string. ; CL- Length of source string. ; ; Note: the strings pointed at by the SI and DI registers are ; length-prefixed strings. That is, the first byte of each ; string contains the length of that string. Substring proc near push ax push cx push di push si clc ;Assume no error. pushf ;Save direction flag status. ; Check the validity of the parameters. cmp ch, [si] ;Is index beyond the length of ja ReturnEmpty ; the source string? mov al, ch ;See if the sum of index and dec al ; length is beyond the end of the add al, cl ; string. jc TooLong ;Error if > 255. cmp al, [si] ;Beyond the length of the source? jbe OkaySoFar ; If the substring isn't completely contained within the source ; string, truncate it: TooLong: popf stc ;Return an error flag. pushf mov al, [si] ;Get maximum length. sub al, ch ;Subtract index value. inc al ;Adjust as appropriate. mov cl, al ;Save as new length. OkaySoFar: mov es:[di], cl ;Save destination string length. inc di mov al, ch ;Get index into source. mov ch, 0 ;Zero extend length value into CX. mov ah, 0 ;Zero extend index into AX. add si, ax ;Compute address of substring. cld rep movsb ;Copy the substring. popf SubStrDone: pop si pop di pop cx pop ax ret ; Return an empty string here: ReturnEmpty: mov byte ptr es:[di], 0 popf stc jmp SubStrDone SubString endp
Index
string function searches for the first occurrence of one string within another and returns the offset to that occurrence. Consider the following HLL form:SourceStr := 'Hello world'; TestStr := 'world'; I := INDEX(SourceStr, TestStr);
The Index
function scans through the source string looking for the first occurrence of the test string. If found, it returns the index into the source string where the test string begins. In the example above, the Index
function would return seven since the substring 'world' starts at the seventh character position in the source string.
The only possible error occurs if Index
cannot find the test string in the source string. In such a situation, most implementations return zero. Our version will do likewise. The Index
function which follows operates in the following fashion:
1) It compares the length of the test string to the length of the source string. If the test string is longer, Index
immediately returns zero since there is no way the test string will be found in the source string in this situation.
2) The index
function operates as follows:
i := 1; while (i < (length(source)-length(test)) and test <> substr(source, i, length(test)) do i := i+1;
When this loop terminates, if (i < length(source)-length(test)) then it contains the index into source where test begins. Otherwise test is not a substring of source. Using the previous example, this loop compares test to source in the following manner:
i=1 test: world No match source: Hello world i=2 test: world No match source: Hello world i=3 test: world No match source: Hello world i=4 test: world No match source: Hello world i=5 test: world No match source: Hello world i=6 test: world No match source: Hello world i=7 test: world Match source: Hello world
There are (algorithmically) better ways to do this comparison[7], however, the algorithm above lends itself to the use of 80x86 string instructions and is very easy to understand. Index
's code follows:
; INDEX- computes the offset of one string within another. ; ; On entry: ; ; ES:DI- Points at the test string that INDEX will search for ; in the source string. ; DS:SI- Points at the source string which (presumably) ; contains the string INDEX is searching for. ; ; On exit: ; ; AX- Contains the offset into the source string where the ; test string was found. INDEX proc near push si push di push bx push cx pushf ;Save direction flag value. cld mov al, es:[di] ;Get the length of the test string. cmp al, [si] ;See if it is longer than the length ja NotThere ; of the source string. ; Compute the index of the last character we need to compare the ; test string against in the source string. mov al, es:[di] ;Length of test string. mov cl, al ;Save for later. mov ch, 0 sub al, [si] ;Length of source string. mov bl, al ;# of times to repeat loop. inc di ;Skip over length byte. xor ax, ax ;Init index to zero. CmpLoop: inc ax ;Bump index by one. inc si ;Move on to the next char in source. push si ;Save string pointers and the push di ; length of the test string. push cx rep cmpsb ;Compare the strings. pop cx ;Restore string pointers pop di ; and length. pop si je Foundindex ;If we found the substring. dec bl jnz CmpLoop ;Try next entry in source string. ; If we fall down here, the test string doesn't appear inside the ; source string. NotThere: xor ax, ax ;Return INDEX = 0 ; If the substring was found in the loop above, remove the ; garbage left on the stack FoundIndex: popf pop cx pop bx pop di pop si ret INDEX endp
Repeat
string function expects three parameters- the address of a string, a length, and a character. It constructs a string of the specified length containing "length" copies of the specified character. For example, Repeat(STR,5,'*')
stores the string '*****' into the STR
string variable. This is a very easy string function to write, thanks to the stosb
instruction:; REPEAT- Constructs a string of length CX where each element ; is initialized to the character passed in AL. ; ; On entry: ; ; ES:DI- Points at the string to be constructed. ; CX- Contains the length of the string. ; AL- Contains the character with which each element of ; the string is to be initialized. REPEAT proc near push di push ax push cx pushf ;Save direction flag value. cld mov es:[di], cl ;Save string length. mov ch, 0 ;Just in case. inc di ;Start string at next location. rep stosb popf pop cx pop ax pop di ret REPEAT endp
Insert
string function inserts one string into another. It expects three parameters, a source string, a destination string, and an index. Insert
inserts the source string into the destination string starting at the offset specified by the index parameter. HLLs usually call the Insert
procedure as follows:source := ' there'; dest := 'Hello world'; INSERT(source,dest,6);
The call to Insert
above would change source to contain the string 'Hello there world'. It does this by inserting the string ' there' before the sixth character in 'Hello world'.
The insert procedure using the following algorithm:
Insert(Src,dest,index);
1) Move the characters from location dest+index
through the end of the destination string length
(Src
) bytes up in memory.
2) Copy the characters from the Src
string to location dest+index
.
3) Adjust the length of the destination string so that it is the sum of the destination and source lengths. The following code implements this algorithm:
; INSERT- Inserts one string into another. ; ; On entry: ; ; DS:SI Points at the source string to be inserted ; ; ES:DI Points at the destination string into which the source ; string will be inserted. ; ; DX Contains the offset into the destination string where the ; source string is to be inserted. ; ; ; All registers are preserved. ; ; Error condition- ; ; If the length of the newly created string is greater than 255, ; the insert operation will not be performed and the carry flag ; will be returned set. ; ; If the index is greater than the length of the destination ; string, ; then the source string will be appended to the end of the destin- ; ation string. INSERT proc near push si push di push dx push cx push bx push ax clc ;Assume no error. pushf mov dh, 0 ;Just to be safe. ; First, see if the new string will be too long. mov ch, 0 mov ah, ch mov bh, ch mov al, es:[di] ;AX = length of dest string. mov cl, [si] ;CX = length of source string. mov bl, al ;BX = length of new string. add bl, cl jc TooLong ;Abort if too long. mov es:[di], bl ;Update length. ; See if the index value is too large: cmp dl, al jbe IndexIsOK mov dl, al IndexIsOK: ; Now, make room for the string that's about to be inserted. push si ;Save for later. push cx mov si, di ;Point SI at the end of current add si, ax ; destination string. add di, bx ;Point DI at the end of new str. std rep movsb ;Open up space for new string. ; Now, copy the source string into the space opened up. pop cx pop si add si, cx ;Point at end of source string. rep movsb jmp INSERTDone TooLong: popf stc pushf INSERTDone: popf pop ax pop bx pop cx pop dx pop di pop si ret INSERT endp
Delete
string removes characters from a string. It expects three parameters - the address of a string, an index into that string, and the number of characters to remove from that string. A HLL call to Delete
usually takes the form:Delete(Str,index,length);
For example,
Str := 'Hello there world'; Delete(str,7,6);
This call to Delete
will leave str containing 'Hello world'. The algorithm for the delete operation is the following:
1) Subtract the length parameter value from the length of the destination string and update the length of the destination string with this new value.
2) Copy any characters following the deleted substring over the top of the deleted substring.
There are a couple of errors that may occur when using the delete procedure. The index value could be zero or larger than the size of the specified string. In this case, the Delete
procedure shouldn't do anything to the string. If the sum of the index and length parameters is greater than the length of the string, then the Delete
procedure should delete all the characters to the end of the string. The following code implements the Delete
procedure:
; DELETE - removes some substring from a string. ; ; On entry: ; ; DS:SI Points at the source string. ; DX Index into the string of the start of the substring ; to delete. ; CX Length of the substring to be deleted. ; ; Error conditions- ; ; If DX is greater than the length of the string, then the ; operation is aborted. ; ; If DX+CX is greater than the length of the string, DELETE only ; deletes those characters from DX through the end of the string. DELETE proc near push es push si push di push ax push cx push dx pushf ;Save direction flag. mov ax, ds ;Source and destination strings mov es, ax ; are the same. mov ah, 0 mov dh, ah ;Just to be safe. mov ch, ah ; See if any error conditions exist. mov al, [si] ;Get the string length cmp dl, al ;Is the index too big? ja TooBig mov al, dl ;Now see if INDEX+LENGTH add al, cl ;is too large jc Truncate cmp al, [si] jbe LengthIsOK ; If the substring is too big, truncate it to fit. Truncate: mov cl, [si] ;Compute maximum length sub cl, dl inc cl ; Compute the length of the new string. LengthIsOK: mov al, [si] sub al, cl mov [si], al ; Okay, now delete the specified substring. add si, dx ;Compute address of the substring mov di, si ; to be deleted, and the address of add di, cx ; the first character following it. cld rep movsb ;Delete the string. TooBig: popf pop dx pop cx pop ax pop di pop si pop es ret DELETE endp
Concat('Hello ','world')
produces the string 'Hello world'. Some high level languages treat concatenation as a function call, others as a procedure call. Since in assembly language everything is a procedure call anyway, we'll adopt the procedural syntax. Our Concat
procedure will take the following form:Concat(source1,source2,dest);
This procedure will copy source1
to dest
, then it will concatenate source2
to the end of dest
. Concat
follows:
; Concat- Copies the string pointed at by SI to the string ; rointed at by DI and then concatenates the string; ; pointed at by BX to the destination string. ; ; On entry- ; ; DS:SI- Points at the first source string ; DS:BX- Points at the second source string ; ES:DI- Points at the destination string. ; ; Error condition- ; ; The sum of the lengths of the two strings is greater than 255. ; In this event, the second string will be truncated so that the ; entire string is less than 256 characters in length. CONCAT proc near push si push di push cx push ax pushf ; Copy the first string to the destination string: mov al, [si] mov cl, al mov ch, 0 mov ah, ch add al, [bx] ;Compute the sum of the string's adc ah, 0 ; lengths. cmp ax, 256 jb SetNewLength mov ah, [si] ;Save original string length. mov al, 255 ;Fix string length at 255. SetNewLength: mov es:[di], al ;Save new string length. inc di ;Skip over length bytes. inc si rep movsb ;Copy source1 to dest string. ; If the sum of the two strings is too long, the second string ; must be truncated. mov cl, [bx] ;Get length of second string. cmp ax, 256 jb LengthsAreOK mov cl, ah ;Compute truncated length. neg cl ;CL := 256-Length(Str1). LengthsAreOK: lea si, 1[bx] ;Point at second string and ; ; skip the string length. cld rep movsb ;Perform the concatenation. popf pop ax pop cx pop di pop si ret CONCAT endp